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81 lines
1.8 KiB
Go
81 lines
1.8 KiB
Go
package main
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import (
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"fmt"
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"log"
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)
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const (
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prefix = "SFDashC"
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// Log Levels
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ERROR = iota
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WARNING = iota
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INFO = iota
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DEBUG = iota
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)
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var logLevel int
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func init() {
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logLevel = INFO
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}
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func getLevelText() string {
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switch logLevel {
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case ERROR:
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return "ERROR"
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case WARNING:
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return "WARNING"
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case INFO:
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return "INFO"
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case DEBUG:
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return "DEBUG"
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default:
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return "UNKNOWN"
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}
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}
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func getLogPrefix() string {
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return fmt.Sprintf("%s: %s:", prefix, getLevelText())
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}
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// SetLogLevel will set the maximum level to print
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func SetLogLevel(level int) {
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logLevel = level
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}
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// Log will print a formatted message with a prefix for a specified level
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// If the level is greater than the maximum log level, it will not print
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func Log(level int, format string, a ...interface{}) {
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if level <= logLevel {
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message := fmt.Sprintf(format, a...)
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message = fmt.Sprintf("%s: %s: %s", prefix, getLevelText(), message)
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log.Println(message)
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}
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}
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// LogError will print an error message
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// If the level is greater than the maximum log level, it will not print
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// It is recommended to use log.Fatal() instead since it will handle exits for you
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func LogError(format string, a ...interface{}) {
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Log(ERROR, format, a...)
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}
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// LogInfo will print a warning message
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// If the level is greater than the maximum log level, it will not print
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func LogWarning(format string, a ...interface{}) {
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Log(WARNING, format, a...)
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}
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// LogInfo will print an info message
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// If the level is greater than the maximum log level, it will not print
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func LogInfo(format string, a ...interface{}) {
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Log(INFO, format, a...)
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}
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// LogDebug will print an debug message
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// If the level is greater than the maximum log level, it will not print
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func LogDebug(format string, a ...interface{}) {
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Log(DEBUG, format, a...)
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}
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